x^2-(x-4)2=128

Solution for x^2-(x-4)2=128 equation:

Simplifying
x2 + -1(x + -4) * 2 = 128

Reorder the terms:
x2 + -1(-4 + x) * 2 = 128

Reorder the terms for easier multiplication:
x2 + -1 * 2(-4 + x) = 128

Multiply -1 * 2
x2 + -2(-4 + x) = 128
x2 + (-4 * -2 + x * -2) = 128
x2 + (8 + -2x) = 128

Reorder the terms:
8 + -2x + x2 = 128

Solving
8 + -2x + x2 = 128

Solving for variable 'x'.

Reorder the terms:
8 + -128 + -2x + x2 = 128 + -128

Combine like terms: 8 + -128 = -120
-120 + -2x + x2 = 128 + -128

Combine like terms: 128 + -128 = 0
-120 + -2x + x2 = 0

Factor a trinomial.
(-10 + -1x)(12 + -1x) = 0

Subproblem 1
Set the factor '(-10 + -1x)' equal to zero and attempt to solve:

Simplifying
-10 + -1x = 0

Solving
-10 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + -1x = 0 + 10

Combine like terms: -10 + 10 = 0
0 + -1x = 0 + 10
-1x = 0 + 10

Combine like terms: 0 + 10 = 10
-1x = 10

Divide each side by '-1'.
x = -10

Simplifying
x = -10
Subproblem 2
Set the factor '(12 + -1x)' equal to zero and attempt to solve:

Simplifying
12 + -1x = 0

Solving
12 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1x = 0 + -12
-1x = 0 + -12

Combine like terms: 0 + -12 = -12
-1x = -12

Divide each side by '-1'.
x = 12

Simplifying
x = 12
Solution
x = {-10, 12}